Instantaneous velocity:-
♻️Instantaneous velocity:-
V=√u2+g2t2
If β be the angle which V makes with the horizontal, then,
β = tan-1(-gt/u)
Projectile fired at angle α with the vertical:-
Time of Ascent, t = (u cosα)/g
Total time of Flight, T = (2u cosα)/g
Horizontal Range, R = u2sin2α/g
Maximum Height, H = u2cos2α/2g
Equation of trajectory, y = x cotα-(gx2/2u2sin2α)
Instantaneous velocity, V=√(u2+g2t2-2ugt cosα) and β = tan-1(ucosα-gt/usinα)
Projectile fired from the base of an inclined plane:-
Horizontal Range, R = 2u2 cos(α+β) sinβ/gcos2α
Time of flight, T = 2u sinβ/ gcosα
Here, α+β=θ
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