Instantaneous velocity:-

♻️Instantaneous velocity:-

V=√u2+g2t2

If β be the angle which V makes with the horizontal, then,

β = tan-1(-gt/u)

Projectile fired at angle α with the vertical:-

Time of Ascent, t = (u cosα)/g

Total time of Flight, T = (2u cosα)/g

Horizontal Range, R = u2sin2α/g

Maximum Height, H = u2cos2α/2g

Equation of trajectory, y = x cotα-(gx2/2u2sin2α)

Instantaneous velocity, V=√(u2+g2t2-2ugt cosα) and β = tan-1(ucosα-gt/usinα)

Projectile fired from the base of an inclined plane:-

Horizontal Range, R = 2u2 cos(α+β) sinβ/gcos2α

Time of flight, T = 2u sinβ/ gcosα

Here, α+β=θ

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